How do I make a function return a char array?

My function ends with:


return letter[count];


It is supposed to return a character for letter0, letter1, letter2...





This is my entire function:


char assignletters (int v[100], int j)


{


char letter[30];


for (int count=0; count%26lt;j; count++){


if (v[count]%26gt;92)


letter[count]='A';


if (v[count]%26gt;82)


letter[count]='B';


if (v[count]%26gt;72)


letter[count]='C';


if (v[count]%26gt;64)


letter[count]='D';


if (v[count]%26lt;65)


letter[count]='F';


cout%26lt;%26lt;"Grade"%26lt;%26lt;"/t"%26lt;%26lt;"Letter"%26lt;%26lt;endl;


cout%26lt;%26lt;v[count]%26lt;%26lt;"/t"%26lt;%26lt;letter[count];





return letter[count];


}


}


How do I get it to return a character for letter0, letter1, letter2 (the array)?


Thanks!

How do I make a function return a char array?
Change your function signature to return a char array, rather than a single char.





char[] assignletters (int v[100], int j)


{





}
Reply:try using pointers