string lab10identification(){
string labId = "lab 10 Jkim jhk0042@unt.edu";
return labId;
}
char getLetterGrade(int gradeIn) {
if (gradeIn %26gt;= 90 %26amp;%26amp; gradeIn %26lt;= 100)
return 'A';
if (gradeIn %26gt;= 80 %26amp;%26amp; gradeIn %26lt;= 90)
return 'B';
if (gradeIn %26gt;= 70 %26amp;%26amp; gradeIn %26lt;= 80)
return 'C';
if (gradeIn %26gt;= 60 %26amp;%26amp; gradeIn %26lt;= 70)
return 'D';
if (gradeIn %26gt;= 0 %26amp;%26amp; gradeIn %26lt;= 59)
return 'F';
}
int getNumericGrade(){
int grade;
cout %26lt;%26lt; "Enter a grade(-1 to 100, -1 to stop): ";
cin %26gt;%26gt; grade;
return grade;
}
int main() {
int grade;
char letterGrade;
string labId;
lab10identification();
do {
grade = getNumericGrade();
if (grade != -1) {
letterGrade = getLetterGrade(grade);
cout %26lt;%26lt; "The student's letter grade is: " %26lt;%26lt; letterGrade %26lt;%26lt; endl;
}
else if(grade %26lt; -1 %26amp;%26amp; grade %26gt; 100)
cout %26lt;%26lt; "The number is out of range. Try again" %26lt;%26lt; endl;
}
while (grade != -1);
cout %26lt;%26lt; "Good-bye" %26lt;%26lt; endl;
I need help fixing my C++ function program!!?
You need to swap the conditions in your if %26amp; else if statements.
Also, it should be (grade %26lt; -1 || grade %26gt; 100). With %26amp;%26amp; it will never work.
Reply:ok look, the return statement is NOT to print to the screen
if you wanna print from that function you have to do something like
string lab10identification(){
string labId = "lab 10 Jkim jhk0042@unt.edu";
cout %26lt;%26lt; labld;
return labId;
}
and the reason why your check for a wrong number is not working is because when you do this...
else if(grade %26lt; -1 %26amp;%26amp; grade %26gt; 100)
the value of grade can NEVER be LESS than -1 AND greater than 100
you need the OR ( || ) operator instead of AND
because by using the and operator it goes back to the do-segment ..since the value is -6...and it gets into the if( number!= -1) and it prints for a number...รบ
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